TOJC : 2.4

boldtbm@PLU.edu
Tue, 17 Sep 1996 01:35:17 -0800 (PST)

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I have some trouble understanding A. in this problem. My problem is with
constitutional isomers:
The first and most obvious way for me to write the condensed formula is:
CH3CH2CH2CH2Br Which works fine as a primary alkyl

Now for my problem; I wrote the second as:
CH3CH2CH2CHBr
|
CH3
Opps...Never mind I see my problem is that this no longer is a primary
alkyl. The way I wrote it would make it secondary....Sorry to bother you
guys, but I answered my own question and I don't want to erase all of this.
Brian

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