Re: TOJC--9.26a&b

holumma@plu.edu
Fri, 06 Dec 1996 07:20:09 -0800 (PST)

I think the reason the combination of two alkyl radicals wasn't used is
because the yield would be very low. The product we are looking for would
be formed in a chain terminating step which give products that are of low
concentration in the solution. The majority of the molecules in a radical
reaction will be alkyl halides from the chain propagating steps.

On Fri, 6 Dec 1996 mcgillsa@plu.edu wrote:

> Candi,
>
> I was wondering the same thing myself... I did the reaction that way too.
> I wonder what's right, since no one has responded. :)
> Shana
>
> On Mon, 2 Dec 1996 ulamce@plu.edu wrote:
>
> > HI there! I had a question about 9.26a&b. The problem says to outline a
> > synthesis for different compounds. For a and b, the answer book uses a
> > lithium dialkylcuprate reaction to combine the the alkyl chains, using
> > radical reactions to produce the alkyl halides for the (R2)LiCu reaction.
> > My question is why you can't just have the two alkane chains react with
> > radicals to produce alkyl radicals, and then have the two alkyl radicals
> > combine to form the longer alkyl chain? Wouldn't this be a possible
> > chain-terminating step that could happen in the reaction if you had both
> > alkanes present originally in the mixture?
> >
> > Hopefully someone understood what I was babling about.... =)
> >
> > ulamce
> >
> >
>
>