Once again! :) Well, yes, the EN's of C and H are similar, but if you
have an EN atom attatched to the molecule and you are looking at the
spectra for that atom (1H or 13C) the deshielded atoms are going to appear
more downfield...because of the electron drawing effects of the EN atom.
I think we may have beaten this to death!! :)
Shana M.
> Shana~
> Excellent point. I believe the near equal EN's of carbon and hydrogen are
> the key to this puzzler. Does this sound feasible to you?
>
> Kelly
>
> On Mon, 9 Dec 1996 mcgillsa@plu.edu wrote:
>
> > Kelly,
> > Doesn't drawing the electrons towards the nuclei of the more EN atom also
> > draw away (deshield) the electrons from the other remaining atom??
> > Just a thought...
> > Shana M.
> >
> > >
> > > Sandy~
> > > My understanding is that the greater EN doesn't reduce the electron
> > > density of atoms but draws the electrons towards the nuclei of the bonded
> > > atoms and away from the sigma bonds. This greater electron
> > > density at the protons shields the protons.
> > >
> > > Anybody else?
> > >
> > > Kelly Mainard
> > >
> > > On Mon, 9 Dec 1996 lwaisk@plu.edu wrote:
> > >
> > > >
> > > > Hi Guys,
> > > > This question is to help me preparing for the final.
> > > > Why does a greater electronegativity reduces the electron density of an
> > > > atom and reduces its shielding?
> > > >
> > > > Sandy
> > > >
> > > >
> > >
> > >
> >
> >
>
>