Re: tojc: solubility

ulamce@plu.edu
Fri, 13 Dec 1996 22:50:45 -0800 (PST)

I don't have the slightest clue about whether the solubility reasons are
right, but another possibility could be because of the character of the
salt. Ionizing a carbon chain to its negative ion (R-) and bonding it
ionically to a metal creates a polar/ ionic molecule. Because it is
polar, it can then dissolve in water, a polar solvent. Having a carbon of
chain of more than 5 carbons would result in a nonpolar molecule, which
would not dissolve in a polar solvent (water).

This might also incorporate hydrogen bonding somehow, but I don't know how
(or if I learned last year, I sure don't remember it now).

Hope I'm right...or at least not completely wrong.

ulamce

On Fri, 13 Dec 1996, Allister Stone wrote:

> I think that all group one elements are highly soluble.
>
> Allister
> ps. you could check inorganic chem book to double check.as
>
> On Fri, 13 Dec
> 1996 partaina@plu.edu wrote:
>
> > Date: Fri, 13 Dec 1996 11:28:08 -0800 (PST)
> > From: partaina@plu.edu
> > To: fosliejf@plu.edu
> > Cc: organic@rainier.chem.plu.edu
> > Subject: Re: tojc: solubility
> >
> > Justin,
> > I have to review my inorganic big time but I would hazard to guess that
> > the Na+ offers a way for hydrogen bonding to occur so solubility is
> > increased.
> > Neil
> >
> > On Fri, 13 Dec 1996 fosliejf@plu.edu wrote:
> >
> > >
> > > I was reviewing some old stuff in chapter three and noted that a compound
> > > with 5 or more carbons is insoluble in water. However if the coumpound
> > > has 5 carbons and is a salt it is able to dissolve in water. What does
> > > the added Na+ or other ion do to make it soluble? Any insights are
> > > appreciated.
> > >
> > > Justin
> > >
> > >
> >
> >
>
>