Re: Ch 11

ulamce@plu.edu
Sun, 15 Dec 1996 16:01:48 -0800 (PST)

No, I don't think it would work, at least not the way you have it written.
If you started w/ phunyl magnesium bromide (I'm assuming that's what you
meant) and the ester you gave, you should end up with
O
||
(C6H5)2CCH2CH3
The RMgX reagent will react twice because it was originally an ester, so
there'd be 2 phenyl groups and an ethyl group attached to the C bearing
the OH.

Also, I don';t know if it was just a typo, but you had one too many H in
your possible product.

One possible way that (I think) would work to form phenyl-CH(OH)Et would
be to start with phenyl-MgBr and O=CHCH2CH3.

On Sun, 15 Dec 1996 kullnaja@plu.edu wrote:

>
> On problem 10a, if you started with phenyl magnesium and 0
> ||
> H3C-O-C-CH2-CH3
> would it work to form phenyl-CH(OH)H-CH2-Ch3?
>
> Thanks
>
> jon
>
>