Re: bicyclic compounds

Firefly (muellesb@plu.edu)
Mon, 03 Mar 1997 17:41:38 -0800 (PST)

I'd like to add/amend....
regarding the numbers in parentheses, I'll call them [x,y,z]:

x refers to the number of carbons in the larger ring (not always on the
left) (excluding any carbons in the bridge)
y refers to the number of carbons in the smaller ring (not always on
the right) (excluding any carbons in the bridge)
z refers to the number of carbons within the bridge (excluding
bridgeheads)
I hope that makes it easy to understand!

On Mon, 3 Mar 1997 sounthna@plu.edu wrote:

> The [4.4.0] comes from the how many carbons there are on each end of the
> molecue and the middle or bridging molecues. The first number represents
> lets say the left side, the second represents the right side, and the last
> represents the brigde or middle of a molecue. A good example is on page
> 139 problem 4.6(c). If you look at the left side there is one carbon, on
> the right side there are two carbons and there is one carbon in the middle
> or bridging the left and right side. So the name for problem 4.6(c) is
> bycyclo[2.1.1]hexane. For problem 4.6(e) the name would be
> 2-methylbicyclo[2.2.2]octane. The left side has two carbons, the right
> side has two carbons and the middle has two sticking up. Since the methyl
> group is on one of the two carbon ends it's named 2-methyl. The book
> tries to help you see this by bending the left and right side with
> respects to the middle. Sorry for the long explanation but I hope that
> helped
>
> Nope
>
> On Sun, 2 Mar 1997 weinmadj@plu.edu wrote:
>
> >
> > How do you classify a bicyclic and polycylic alkanes? For example, the
> > name of decalin is bicylo[4.4.0]decane. Where does the [4.4.0] come
> > from and how do you get it?
> >
> > David
> >
> >
>
>